No. 241 · August 24, 2026 · Gentle

Rebuild Required

Implement MyRequired<T> so every optional property becomes required. This is the exact inverse of puzzle #219.

Try the puzzle yourself

Par 2

Puzzle

rebuild-required.ts

interface Draft {
  title?: string
  body?: string
}

type MyRequired<T> = ???

type MyRequired<T> = ???

Stroke 1 of 2Not run yet

Replace ??? — your solution is checked against the cases below. Tab indents; press Escape then Tab to move focus out.

Checks

MyRequired<Draft>—
→ { title: string; body: string }
MyRequired<{ a?: number }>—
→ { a: number }
MyRequired<{ a: string }>—
→ { a: string }

How a check is judged Exact type equality, not assignability — an intersection is not the same as the flattened object.

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Annotated solution

Published August 25, 2026

The solution

type MyRequired<T> = { [K in keyof T]-?: T[K] }

The common wrong answer

type MyRequired<T> = { [K in keyof T]: T[K] }

This is the identity mapping, and that is the surprise: a mapped type over keyof T is *homomorphic*, so it copies the existing ? and readonly modifiers across rather than dropping them. Optional properties stay optional, and the type is unchanged.

Line by line

-?
The minus subtracts the modifier. It does two things at once: the key stops being optional, and undefined is removed from the value type — which is why title?: string becomes title: string and not title: string | undefined.
{ [K in keyof T]
Mapping directly over keyof T is what makes this homomorphic, and homomorphic is what makes modifiers inheritable in the first place. Map over a computed key set instead and every modifier is lost by default.

Takeaway

+ and - before ? or readonly are the only way to change a property’s modifiers. Without them a mapped type quietly preserves whatever was already there, which makes "nothing happened" a very common bug.

Uses

Mapped types Partial Required Pick Omit Record Mapped types Make Omit catch typos Flatten an intersection Require at least one property Make two prop shapes mutually exclusive